Quadratic Inequality


  • From: Sarah
  • Date: 26 December 1999
  • Subject: Quadratic Inequalities

How do you solve 4x^2 - 4x + 1 > 4 ?


Maths Help suggests:

First, consider solving the quadratic equation:

4x2 - 4x + 1 = 4

The first step is to collect all the terms together, leaving '=0' on the right hand side:

4x2 - 4x - 3 = 0

Solving by factorisation:

(2x - 3) (2x + 1) = 0

2x - 3 = 0   or   2x + 1 = 0

x = 1.5   or   x = -0.5

But we wish to solve the inequality:

4x2 - 4x - 3 > 0

Graph of  y = 4x^2 - 4x - 3

Now consider a sketch of the graph  y = 4x2 - 4x - 3   (right).

The graph (a 'U'-shaped parabola) shows that the function is greater than zero
  to the left of the root at -0.5   and
  to the right of the root at 1.5

So the solution to the equation  x2 - 4x + 1 > 4  is:

x < -0.5  or  x > 1.5


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